What is the equation of the line in slope-intercept form?

Line on a coordinate plane. The line runs through points begin ordered pair negative 5 comma 0 end ordered pair and begin ordered pair 0 comma 3 end ordered pair.

What is the equation of the line in slopeintercept form Line on a coordinate plane The line runs through points begin ordered pair negative 5 comma 0 end ordere class=

Respuesta :


[tex]y = \frac{3}{5} x + 3[/tex]

Answer: [tex]y= \dfrac{3}{5}x+3[/tex]

Step-by-step explanation:

The equation of the line in slope-intercept form is given by :-

[tex]y= mx+b[/tex]            (1)

, where m= slope of line  and b = y-intercept.            

From the given graph , it can be seen that the y-intercept of graph is at  y= 3.

⇒b=3            (2)

Also, the slope of a line passing through two points (a,b) and (c,d) is given by :-

[tex]m=\dfrac{d-b}{c-a}[/tex]

The slope of given line passing through (-5,0) and (0,3) will be :_

[tex]m=\dfrac{3-0}{0-(-5)}=\dfrac{3}{5}[/tex]  (3)

Substitute value of b and m from (2) and (3) respectively in equation (1), we get

[tex]y= \dfrac{3}{5}x+3[/tex]

Hence, the equation of the line in slope-intercept form : [tex]y= \dfrac{3}{5}x+3[/tex]

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