Which is a zero of the quadratic function f(x) = 4x^2 + 24x + 11

Answer:
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Step-by-step explanation: the answer is B
The zero of the given quadratic equation will be x = -69.5.
The polynomial having a degree of two or the maximum power of the variable in a polynomial will be 2 is defined as the quadratic equation and it will cut two intercepts on the graph at the x-axis.
Here we are having an equation:-
4x² + 24x + 11 = 0
By using the formula:-
[tex]x = \dfrac{-b+\sqrt{b^2-4ac}}{4a}[/tex]
[tex]x = \dfrac{-(24)^2+\sqrt{(24^2)-(4\times 4\times 11}}{4\times 2}[/tex]
[tex]x = \dfrac{-576+20}{8}[/tex]
x = -69.5
Therefore the zero of the given quadratic equation will be x = -69.5.
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