Question

What I'd the equation of a line that passes through points (-2,6) and (4,-3)?

Answer 1

slope = (y2-y1)/(x2-x1)

 m = (-3-6)/(4--2)

  = -9/6

=-3/2

y -y1 = m(x-x1)

y-6 =-3/2 (x--2)

y-6 =-3/2 (x+2)

y-6  =-3/2 x -3

add 6

y = -3/2 x +3