The least common denominator that can be used to add and is 24x2. What value of b is needed to rewrite the first fraction with the LCD?

[tex]\frac{x+1}{8x^2}[/tex] and [tex]\frac{2x-3}{12x}[/tex]
LCD is 24x^2
we need to find out b when multiply with first fraction to get 3x+3/24x^2
[tex]\frac{x+1}{8x^2} (\frac{b}{b}) =\frac{3x+3}{24x^2}[/tex]
We need to find out a number what multiply with 8x^2 to get 24x^2
[tex]8x^2 * 3 = 24x^2[/tex]
[tex]\frac{x+1}{8x^2} (\frac{3}{3}) =\frac{3(x+1)}{24x^2}=\frac{3x+3}{24x^2}[/tex]
So the value of b is 3