a quadratic function given the roots (3,0) and (-1,0) and the point (-3,3)
when p and q are the roots then we use equation
y = a(x- p)(x-q)
We are given with roots 3 and -1
y = a(x- 3)(x-(-1))
y = a(x- 3)(x + 1)
Now we use the given point (-3,3) to find out 'a'
3 = a(-3- 3)(-3 + 1)
3= a(-6)(-2)
3= 12a
divide by 12 on both sides
[tex]a= \frac{1}{4}[/tex]
Replace the value of 'a'
[tex]f(x)= \frac{1}{4}(x-3)(x+1)[/tex]
