Question

A feather is dropped on the moon from a height of 1.4 meters. The acceleration of gravity on the moon is 1.67 m/s^2. Calculate time for the feather to fall to the surface of the moon.

Answer 1

The initial velocity of feather=0

By equation
v^2 =u^2+2as

v^2=0 +2(1.67)(1.4)

v^2=4.67

v=√4.67
v=2.16m/s

Now we have final velocity when feather touches the surface of moon.

Using the equation
v=u +at

2.16 =0+1.67t
t=2.16/1.67
t=1.3sec