Question

Who Am I?

• I am a three-digit number

• At least two of my digits are perfect squares.

• u>t

• Only only of my digits is even

• u=2h+1

• My ten digit is two less than my unit digit.

• t-h=3

• One of my digit is 7

please help me!!!

Answer 1

Answer:

479

Step-by-step explanation:

1. The number you want is between 100 and 999
2. At least two of the digits are perfect squares 1 4 9 are the perfect squares.
3. Units > tens; units are 2 to 9 ; tens are 1 to 8
4. 1 even in the result; the other two are in 1 3 5 7 or 9
5. The units digit is larger than the hundreds digit. The units digit is odd.
6. t = unit - 2. the two odd digits are the tens and the units.
7. t - h= 3
8. one of the digits is 7

The units digit cannot be 1 That would make the 10s digit - 1. The tens digit cannot be 9. That would make the units digits 11.

Let's try x79 If that is correct, the hundreds digit is 4 because the hundreds digit is three less than the tens.

Answer: 479

479 is between 100 and 999. 4 and 9 are perfect squares. u>t. 4 is the only even number.