Makbear Makbear

28-10-2018
Mathematics

contestada

8<2/3(3y-6)
[tex]8 \leqslant \frac{2}{3} (3y - 6)[/tex]

Respuesta :

wegnerkolmp2741o wegnerkolmp2741o

28-10-2018

8<=2/3(3y-6)

distribute

8<= 2y -4

add 4 to each side

12 <=2y

divide by 2

6<=y

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