Question

rearrange this for z
$4z {}^{3} = \frac{(x {}^{ \frac{1}{2} }y {}^{ - 3}z) {}^{2} }{ y - s }$

Answer 1

$4z^3=\frac{(x^{1/2}y^{-3}z)^2}{y-s}=\frac{(x^{1/2}y^{-3})^2z^2}{y-s}\\4\frac{z^3}{z^2}(=4z)=\frac{(x^{1/2}y^{-3})^2}{y-s}\\z = \frac{(x^{1/2}y^{-3})^2}{4(y-s)}$

Answer 2

Answer:

z = x/[4y⁶(y - 8)]

Step-by-step explanation:

Distribute the powers

4z³ = (x × y^-6 × z²)/(y - 8

Divide both sides by 4z²

z = (x × y^-6)/4(y - 8)

z = x/[4y⁶(y - 8)]