Answer:
Apparent power is 1.413Volt-Amps.
Step-by-step explanation:
We are given that in a parallel circuit,[tex]E_{T}=208V[/tex],R=33kΩ and [tex]X_{L}[/tex]=82kΩ.
And we are asked to find apparent power.
Apparent power is the combination of true power and reactive power.
In other words, we can say that in a power triangle apparent power is the hypotenuse where as true power and reactive powers are sides.
Let us find true power , reactive power first and the using Pythagorean theorem we can find apparent power.
True power=[tex]\frac{E_{T}^{2}}{R}=\frac{208^{2}}{33000}=1.311watts[/tex]
Reactive power=[tex]\frac{E_{T}^{2}}{X_{L}}=\frac{208^{2}}{82000}=0.528VARs[/tex]
Hence apparent power=[tex]\sqrt{1.311^{2}+0.528^{2}} =1.413VA[/tex]
