Question

In a parallel circuit, the supply voltage is 120 V, 60 Hz. The resistance is 30 Ω and the inductive reactance is 40 Ω. What is the value of the inductor?

Answer 1

Given : supply voltage = 120V;60 Hz

Inductive Reactance $(X_{L}) = 40$ Ω

The inductive reactance is given by the formula, $X_{L}=Lw$, where L is inductance and $w$ is given by formula, $w = 2\pi(frequency)$

Apply this, we can say that, $L = \frac{X_{L}}{2\pi (frequency)}  = \frac{40}{2(3.14)(60)} = 0.106157 H = 106.157 mH$