What are the domain restrictions of the expression g^2+7g+12/g^2−2g−24 ? Select each correct answer.


g≠−6

g≠4

g≠3

g≠6

g≠−3

g≠−4
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Respuesta :

Answer:

(-infinity, -4) ∪ (-4, 6) ∪ (6, +infinity)

Step-by-step explanation:

Any domain restrictions here stem only from division by zero.  Thus, we take the denominator, g^2−2g−24, and purposely set it to 0, and solve for g:

g^2−2g−24 = 0 => (g-6)(g+4) = 0.  Solving for g, g=6 and g= -4.

This function is defined for all values of g other than 6 and -4.  We could also write the domain as follows: (-infinity, -4) ∪ (-4, 6) ∪ (6, +infinity).

Answer:

g=-4 g=6

Step-by-step explanation:

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