Answer:
6.18 g
Explanation:
We know we will need a balanced equation with masses, moles, and molar masses, so let’s gather all the information in one place.
[tex]M_r[/tex]: 41.99
Na₂SiO₃ + 8HF ⟶ 2NaF + H₂SiF₆ + 3H₂O
n/mol: 0.58
1. Use the molar ratio of NaF:HF to calculate the moles of NaF.
[tex]\text{Moles of NaF} = \text{0.589 mol HF} \times \frac{\text{2 mol NaF}}{\text{8 mol HF}} = \text{0.1472 mol NaF}[/tex]
2. Use the molar mass of NaF to calculate the mass of NaF.
[tex]\text{Mass of NaF} = \text{0.1472 mol NaF} \times \frac{\text{41.99 g NaF}}{\text{1 mol NaF}} = \text{6.18 g NaF}[/tex]
