Question

A race car makes one lap around a track of radius 50 m in 9.0 s. What is the average velocity? *

Answer 1

Given that,

Radius of track, r = 50 m

time , t = 9 s

velocity, v = ?

Distance covered by car in one lap around a track is equal to the circumference of the track.

C = 2 π r = 2 * 3.14 * 50

C = 314.159 m

Distance covered by car, s = 314.159 m

Velocity = distance/ time

V = 314.159 / 9

V = 34.9 m/s

The average velocity of car is 34.9 m/s.

Answer 2

The average velocity of the race car around the track in the given time is 34.9m/s

Given the data in the question;

• Radius of the round track; $r = 50m$

• Time elapsed; $t = 9.0s$

Average velocity; $v = \ ?$

Average velocity

Average velocity is simply the displacement of a particle or object over time. It is the rate of change of position of an object with respect to time.

It is expressed as;

$velocity = \frac{displacement}{time}$

It can also be expressed as;

$v = \frac{circumference}{time} = \frac{2\pi r}{t}$

We substitute our values into the expression above

$v = \frac{1\ circumference }{time} \\\\v = \frac{2\pi r}{t} \\\\v = \frac{2\pi\ *\ 50m}{9.0s}\\ \\v = \frac{314.159m}{9.0s}\\ \\v = 34.9m/s$

Therefore, the average velocity of the race car around the track in the given time is 34.9m/s

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