Question

How many moles of Pb(SO4)2 are equivalent to 186.7 g of Pb(SO4)2

Answer 1

Answer : The number of moles of $Pb(SO_4)_2$ is 0.6156 moles.

Solution : Given,

Mass of $Pb(SO_4)_2$ = 186.7 g

Molar mass of $Pb(SO_4)_2$ = 303.256 g/mole

Formula used :

$\text{ Moles}=\frac{\text{ Given mass}}{\text{ Molar mass}}$

Now we have to calculate the moles of $Pb(SO_4)_2$.

$\text{ Moles of }Pb(SO_4)_2=\frac{\text{ Given mass of }Pb(SO_4)_2}{\text{ Molar mass of }Pb(SO_4)_2}$

$\text{ Moles }{Pb(SO_4)_2}=\frac{186.7g}{303.256g/mole}=0.6156moles$

Therefore, the number of moles of $Pb(SO_4)_2$ is 0.6156 moles.