plz give me the right answer I really need help and will give you brainlist plz.
Solve for x.
3(-2x - 1) = 2(x + 5)
A) -
13
8
B) -
3
4
C)
13
8
D)
3
4
2)
Solve the equation.

3(2x - 1) =
1
2
(4x - 2) + 2
A) -1
B) 1
C) 2
D) -
1
2
3)
Solve the equation.
-4(3 - 2x) + 2x = 2x - 8
A) x = 2
B) x = -1
C) x =
1
2
D) x =
1
3
4)
What is the value of x, when 10(x + 2) = 5(x + 8)?
A) x = 1
B) x = 2
C) x = 4
D) x =
5
6
5)
What is the value of x, when -25(x - 4) = -55(x - 10)?
A) x = 5
B) x = -5
C) x = 8
1
8
D) x = 15
6)
What is the value of x, when -9(x - 5) = x + 22
1
2
?
A) x = 1
3
4
B) x = 2
1
4
C) x = 2
2
3
D) x = 2
3
4
7)



Use the model to solve for x.
A) x = 2
B) x = 4
C) x = 8
D) x = 12
8)



Use the model to solve for x.
A) x = 2
B) x = 4
C) x = 8
D) x = 12
9)



Use the model to solve for x.
A) x = 2
B) x = 6
C) x =
2
5
D) x =
6
5
10)
Find the value of x when 5 - x =
1
2
x + 4
A) -6
B) 2
C)
2
3
D)
3
2
11)
Solve for x.

x - 2x(12 -
1
2
) = 2(4 - 2x) + 20
A) -
14
9
B) -
9
14
C)
14
9
D)
9
14
12)



The model represents an equation. What value of x makes the equation true?
A) 9
B)
9
4
C) −9
D) −
9
4
13)
Solve:

5(r - 1) = 2(r - 4) - 6
A) r = -3
B) r = 3
C) r = 9
D) r = -9
14)
Chloe had a homework assignment that she was working on. She wanted to do well on it, so she was trying to remember her strategy for solving equations with variables on both sides of the equal sign. What would you tell her is the best strategy?
A) Just add everything together, you don't need to pay attention to the variables. You got this, girl!
B) Isolate the variable by using inverse operations, and then look for any parenthesis where you will need to use the distributive property.
C) Go backwards in PEMorDAorS, Combine Like Terms, then use the distributive property.
D) Look for parenthesis and apply the distributive property; combine like terms; move your variable terms to one side and constants to the other side of the equal sign; go in reverse PEMorDAorS to isolate the variable using inverse operations.
15)
Chloe had a homework assignment that she was working on. She wanted to do well on it, so she was trying to remember her strategy for solving equations with variables on both sides of the equal sign. What would you tell her is the best strategy?
A) Just add everything together, you don't need to pay attention to the variables. You got this, girl!
B) Isolate the variable by using inverse operations, and then look for any parenthesis where you will need to use the distributive property.
C) Go backwards in PEMorDAorS, Combine Like Terms, then use the distributive property.
D) Look for parenthesis and apply the distributive property; combine like terms; move your variable terms to one side and constants to the other side of the equal sign; go in reverse PEMorDAorS to isolate the variable using inverse operations.
16)

Four times a number minus 5 is the same as twice the number plus 3
Adam needs to write an equation for the situation above, and then solve. What should Adam write:
A) 4n - 5 = 2n + 3; n = 8
B) 4 - 5 + 2 + 3 = 4
C) 4n - 5 = 2n + 3; n = 4
D) 5 - 4n = 3(2) + 3; n = -1
17)
Solve: -2(y +2) + 5y = 6y + 11
A) y = -.20
B) y = -1
C) y = 1
D) y = -5
18)

4(3x - 1) = 3 + 8x - 11
Dalal had the above question on her homework. Solve the equation.
A) x = 3.75
B) x = 3
C) x = -2
D) x = -1
19)

14 - 2(3p + 1) = 6(4 + p)
Meadow needs help on the math homework for tonight. Above is the equation. What should Meadow do first??
A) subtract 3p from both sides
B) add 14 to both sides
C) combine the 3p and p
D) distribute the -2 to the 3p and 1; distribute the 6 to the 4 and p
20)

14 - 2(3p + 1) = 6(4 + p)
Diego is a rock star with equations and solved the above equation by writing down every step in his notebook. You can be a rock star like Diego, too! Write down the equation and solve for the missing variable using your strategy.
A) p = -3
B) p = -1
C) p = 12
D) p = 6

Respuesta :

Answer:

Part 1) Option A [tex]x=-13/8[/tex]

Part 2) Option B [tex]x=1[/tex]

Part 3) Option C [tex]x=1/2[/tex]

Part 4) Option C [tex]x=4[/tex]

Part 5) Option D [tex]x=15[/tex]

Part 6) Option B [tex]x=2\frac{1}{4}[/tex]

Part 10)  Option B [tex]x=2[/tex]

Part 11) Option A [tex]x=-14/9[/tex]  

Part 13) Option A [tex]r=-3[/tex]

Part 14) Option D

Part 15) Option D

Part 16) Option C [tex]4n-5=2n+3; n = 4[/tex]

Part 17) Option D [tex]y=-5[/tex]

Part 18) Option D [tex]x=-1[/tex]

Part 19) Option D distribute the [tex]-2[/tex] to the [tex]3p[/tex] and [tex]1[/tex]; distribute the [tex]6[/tex] to the [tex]4[/tex] and [tex]p[/tex]

Part 20) Option B  [tex]p=-1[/tex]

Step-by-step explanation:

Part 1) we have

[tex]3(-2x-1)=2(x+5)[/tex]

solve for x

[tex]-6x-3=2x+10[/tex]

[tex]2x+6x=-3-10[/tex]  

[tex]8x=-13[/tex]

[tex]x=-13/8[/tex]

Part 2) we have

[tex]3(2x-1)=\frac{1}{2}(4x-2)+2[/tex]

solve for x

[tex]6x-3=2x-1+2[/tex]

[tex]6x-2x=-1+2+3[/tex]

[tex]4x=4[/tex]

[tex]x=1[/tex]

Part 3) we have

[tex]-4(3-2x)+2x=2x-8[/tex]

solve for x

[tex]-12+8x+2x=2x-8[/tex]

[tex]8x=-8+12[/tex]

[tex]8x=4[/tex]

[tex]x=1/2[/tex]

Part 4) we have

[tex]10(x+2)=5(x+8)[/tex]

solve for x

[tex]10x+20=5x+40[/tex]

[tex]10x-5x=40-20[/tex]

[tex]5x=20[/tex]

[tex]x=4[/tex]

Part 5) we have

[tex]-25(x-4)=-55(x-10)[/tex]

solve for x

[tex]-25x+100=-55x+550[/tex]

[tex]-25x+55x=550-100[/tex]

[tex]30x=450[/tex]

[tex]x=450/30[/tex]

[tex]x=15[/tex]

Part 6) we have

[tex]-9(x-5)=x+22\frac{1}{2}[/tex]  

solve for x

remember that

[tex]22\frac{1}{2}=\frac{45}{2}[/tex]

[tex]-9x+45=x+\frac{45}{2}[/tex]

[tex]x+9x=45-\frac{45}{2}[/tex]

[tex]10x=\frac{45}{2}[/tex]  

[tex]x=\frac{45}{20}[/tex]

convert to mixed number

[tex]x= \frac{45}{20}=\frac{9}{4}=2\frac{1}{4}[/tex]

Part 7) The model is not included

Part 8) The model is not included

Part 9) The model is not included

Part 10) we have

[tex]5-x=(1/2)(x+4)[/tex]

solve for x

[tex]5-x=(1/2)x+2[/tex]

[tex](1/2)x+x=5-2[/tex]

[tex](3/2)x=3[/tex]

[tex]x=2[/tex]

Part 11) we have

[tex]x-2x(12-(1/2))=2(4-2x)+20[/tex]

solve for x

[tex]x-24x+x=8-4x+20[/tex]

[tex]x-24x+x+4x=8+20[/tex]

[tex]-18x=28[/tex]

[tex]x=-14/9[/tex]        

Part 12) The model is not included

Part 13) we have

[tex]5(r-1)=2(r-4)-6[/tex]

solve for r

[tex]5r-5=2r-8-6[/tex]

[tex]5r-2r=-8-6+5[/tex]

[tex]3r=-9[/tex]

[tex]r=-3[/tex]

Part 14) and  Part 15)

the answer is the option D

Look for parenthesis and apply the distributive property; combine like terms; move your variable terms to one side and constants to the other side of the equal sign; go in reverse PEMorDAorS to isolate the variable using inverse operations

Part 16)

Let

n------> the number

we know that

[tex]4n-5=2n+3[/tex] -----> algebraic expression that represent the situation

solve for n

[tex]4n-2n=3+5[/tex]

[tex]2n=8[/tex]

[tex]n=4[/tex]

Part 17) we have

[tex]-2(y+2)+5y=6y+11[/tex]

solve for y

[tex]-2y-4+5y=6y+11[/tex]

[tex]6y-5y+2y=-4-11[/tex]

[tex]3y=-15[/tex]

[tex]y=-5[/tex]

Part 18) we have

[tex]4(3x-1)=3+8x-11[/tex]

solve for x

[tex]12x-4=8x-8[/tex]

[tex]12x-8x=-8+4[/tex]

[tex]4x=-4[/tex]

[tex]x=-1[/tex]

Part 19) we have

[tex]14 - 2(3p + 1) = 6(4 + p)[/tex]

 [tex]14 - 6p-2 = 24+6p[/tex] ------> distribute the [tex]-2[/tex] to the [tex]3p[/tex] and [tex]1[/tex]; distribute the [tex]6[/tex] to the [tex]4[/tex] and [tex]p[/tex]

Part 20) we have

[tex]14 - 2(3p + 1) = 6(4 + p)[/tex]

step 1

distribute the [tex]-2[/tex] to the [tex]3p[/tex] and [tex]1[/tex]; distribute the [tex]6[/tex] to the [tex]4[/tex] and [tex]p[/tex]

[tex]14 - 6p-2 = 24+6p[/tex]

step 2

Group terms that contain the same variable and move the constant to the other side

[tex]6p+6p=14-2-24[/tex]

step 3

Combine like terms

[tex]12p=-12[/tex]

step 4

Divide by [tex]12[/tex] both sides

[tex]p=-1[/tex]

Answer:

Step-by-step explanation:

what I did was went to the Microsoft math solver and solved it on the bar and click solve then it will tell you how to do it.

5x  

−1=14

 

The derivative of ax  

n

 is nax  

n−1

.

5x  

1−1

 

Subtract 1 from 1.

5x  

0

 

For any term t except 0, t  

0

=1.

5×1

For any term t, t×1=t and 1t=t.

5

try my link

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