Respuesta :
Answer:
Part 1) Option A [tex]x=-13/8[/tex]
Part 2) Option B [tex]x=1[/tex]
Part 3) Option C [tex]x=1/2[/tex]
Part 4) Option C [tex]x=4[/tex]
Part 5) Option D [tex]x=15[/tex]
Part 6) Option B [tex]x=2\frac{1}{4}[/tex]
Part 10) Option B [tex]x=2[/tex]
Part 11) Option A [tex]x=-14/9[/tex]
Part 13) Option A [tex]r=-3[/tex]
Part 14) Option D
Part 15) Option D
Part 16) Option C [tex]4n-5=2n+3; n = 4[/tex]
Part 17) Option D [tex]y=-5[/tex]
Part 18) Option D [tex]x=-1[/tex]
Part 19) Option D distribute the [tex]-2[/tex] to the [tex]3p[/tex] and [tex]1[/tex]; distribute the [tex]6[/tex] to the [tex]4[/tex] and [tex]p[/tex]
Part 20) Option B [tex]p=-1[/tex]
Step-by-step explanation:
Part 1) we have
[tex]3(-2x-1)=2(x+5)[/tex]
solve for x
[tex]-6x-3=2x+10[/tex]
[tex]2x+6x=-3-10[/tex]
[tex]8x=-13[/tex]
[tex]x=-13/8[/tex]
Part 2) we have
[tex]3(2x-1)=\frac{1}{2}(4x-2)+2[/tex]
solve for x
[tex]6x-3=2x-1+2[/tex]
[tex]6x-2x=-1+2+3[/tex]
[tex]4x=4[/tex]
[tex]x=1[/tex]
Part 3) we have
[tex]-4(3-2x)+2x=2x-8[/tex]
solve for x
[tex]-12+8x+2x=2x-8[/tex]
[tex]8x=-8+12[/tex]
[tex]8x=4[/tex]
[tex]x=1/2[/tex]
Part 4) we have
[tex]10(x+2)=5(x+8)[/tex]
solve for x
[tex]10x+20=5x+40[/tex]
[tex]10x-5x=40-20[/tex]
[tex]5x=20[/tex]
[tex]x=4[/tex]
Part 5) we have
[tex]-25(x-4)=-55(x-10)[/tex]
solve for x
[tex]-25x+100=-55x+550[/tex]
[tex]-25x+55x=550-100[/tex]
[tex]30x=450[/tex]
[tex]x=450/30[/tex]
[tex]x=15[/tex]
Part 6) we have
[tex]-9(x-5)=x+22\frac{1}{2}[/tex]
solve for x
remember that
[tex]22\frac{1}{2}=\frac{45}{2}[/tex]
[tex]-9x+45=x+\frac{45}{2}[/tex]
[tex]x+9x=45-\frac{45}{2}[/tex]
[tex]10x=\frac{45}{2}[/tex]
[tex]x=\frac{45}{20}[/tex]
convert to mixed number
[tex]x= \frac{45}{20}=\frac{9}{4}=2\frac{1}{4}[/tex]
Part 7) The model is not included
Part 8) The model is not included
Part 9) The model is not included
Part 10) we have
[tex]5-x=(1/2)(x+4)[/tex]
solve for x
[tex]5-x=(1/2)x+2[/tex]
[tex](1/2)x+x=5-2[/tex]
[tex](3/2)x=3[/tex]
[tex]x=2[/tex]
Part 11) we have
[tex]x-2x(12-(1/2))=2(4-2x)+20[/tex]
solve for x
[tex]x-24x+x=8-4x+20[/tex]
[tex]x-24x+x+4x=8+20[/tex]
[tex]-18x=28[/tex]
[tex]x=-14/9[/tex]
Part 12) The model is not included
Part 13) we have
[tex]5(r-1)=2(r-4)-6[/tex]
solve for r
[tex]5r-5=2r-8-6[/tex]
[tex]5r-2r=-8-6+5[/tex]
[tex]3r=-9[/tex]
[tex]r=-3[/tex]
Part 14) and Part 15)
the answer is the option D
Look for parenthesis and apply the distributive property; combine like terms; move your variable terms to one side and constants to the other side of the equal sign; go in reverse PEMorDAorS to isolate the variable using inverse operations
Part 16)
Let
n------> the number
we know that
[tex]4n-5=2n+3[/tex] -----> algebraic expression that represent the situation
solve for n
[tex]4n-2n=3+5[/tex]
[tex]2n=8[/tex]
[tex]n=4[/tex]
Part 17) we have
[tex]-2(y+2)+5y=6y+11[/tex]
solve for y
[tex]-2y-4+5y=6y+11[/tex]
[tex]6y-5y+2y=-4-11[/tex]
[tex]3y=-15[/tex]
[tex]y=-5[/tex]
Part 18) we have
[tex]4(3x-1)=3+8x-11[/tex]
solve for x
[tex]12x-4=8x-8[/tex]
[tex]12x-8x=-8+4[/tex]
[tex]4x=-4[/tex]
[tex]x=-1[/tex]
Part 19) we have
[tex]14 - 2(3p + 1) = 6(4 + p)[/tex]
[tex]14 - 6p-2 = 24+6p[/tex] ------> distribute the [tex]-2[/tex] to the [tex]3p[/tex] and [tex]1[/tex]; distribute the [tex]6[/tex] to the [tex]4[/tex] and [tex]p[/tex]
Part 20) we have
[tex]14 - 2(3p + 1) = 6(4 + p)[/tex]
step 1
distribute the [tex]-2[/tex] to the [tex]3p[/tex] and [tex]1[/tex]; distribute the [tex]6[/tex] to the [tex]4[/tex] and [tex]p[/tex]
[tex]14 - 6p-2 = 24+6p[/tex]
step 2
Group terms that contain the same variable and move the constant to the other side
[tex]6p+6p=14-2-24[/tex]
step 3
Combine like terms
[tex]12p=-12[/tex]
step 4
Divide by [tex]12[/tex] both sides
[tex]p=-1[/tex]
Answer:
Step-by-step explanation:
what I did was went to the Microsoft math solver and solved it on the bar and click solve then it will tell you how to do it.
5x
−1=14
The derivative of ax
n
is nax
n−1
.
5x
1−1
Subtract 1 from 1.
5x
0
For any term t except 0, t
0
=1.
5×1
For any term t, t×1=t and 1t=t.
5
try my link