The equation of the line in standard form is
[tex]y=mx+b,[/tex] where m is the slope.
Thus, the equation of line is
[tex]y=\dfrac{4}{3}x+b.[/tex]
Since point (-2,5) is point on the line, then
[tex]5=\dfrac{4}{3}\cdot (-2)+b,\\ \\b=5+\dfrac{8}{3}=\dfrac{23}{3}.[/tex]
The equation of the liine is
[tex]y=\dfrac{4}{3}x+\dfrac{23}{3}.[/tex]