Respuesta :

frika

The equation of the line in standard form is

[tex]y=mx+b,[/tex] where m is the slope.

Thus, the equation of line is

[tex]y=\dfrac{4}{3}x+b.[/tex]

Since point (-2,5) is point on the line, then

[tex]5=\dfrac{4}{3}\cdot (-2)+b,\\ \\b=5+\dfrac{8}{3}=\dfrac{23}{3}.[/tex]

The equation of the liine is

[tex]y=\dfrac{4}{3}x+\dfrac{23}{3}.[/tex]

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