Question

Compound a, c10h22o, undergoes reaction with dilute h2so4 at 50°c to yield a mixture of two alkenes, b and c, c10h20. the major alkene product, b, gives only 3-pentanone after ozone treatment followed by reduction with zinc in acetic acid. draw the structure of the major alkene product, compound

b.

Answer 1

Answer :

When compound A, undergoes reaction with dilute $H_2SO_4$ at $50^oC$ to yield a mixture of two alkenes, B and C. In these two alkenes B is the major product and C is the minor product.

According to the saytzeff's rule, the more substituted alkene is formed as a major product during dehydration that means double bond is formed due to loss of water molecule. Dilute $H_2SO_4$ is act as a dehydrating agent.

Now the major product alkene B gives only 3-pentanone after ozonolysis followed by reduction with zinc in acetic acid.

The reaction is shown below.