Question

Vertex Form: y - 2 = -2 (x-4)^2
Standard Form?
Intercept Form?

Answer 1

Answer:

Vertex form : $y=-2(x-4)^2+2$

Intercept Form: $y=-2(x-5)(x-3)$

Step-by-step explanation:

We are given

$y-2=-2(x-4)^2$

Simplifying we get

Adding 2 on both sides

$y=-2(x-4)^2+2$

This is the vertex form

Now

Factoring -2 we get

$y=-2[(x-4)^2-1]$

$y=-2(x-4-1)(x-4+1)$

$y=-2(x-5)(x-3)$

is the intercept form