According to a recent​ study, 14% of u.s. drivers are uninsured. a random sample of seven drivers was selected. what is the probability that none of these drivers are​ uninsured?

Respuesta :

Answer: The probability that none of the drivers are uninsured is 0.3479 or 34.79%.

We can answer this question as follows:

We use the binomial distribution formula in order to find the probability.

The formula is as follows:

[tex]\mathbf{P(X=x) =_{n}^{x}\textrm{C}*p^{x}*q^{(n-x)}}[/tex]

where

n is the total number of trials = 7

x is the number of successes among the trials = 0

p refers to the probability of success = 0.14

q refers to the probability of failure = 1-p = [tex]1-0.14 = 0.86[/tex]

[tex]_{n}^{x}\textrm{C}[/tex] is the combination of choosing x items from a total of n items

Substituting the values we get

[tex]\mathbf{P(X=x) =\frac{n!}{x!*(n-x)!}*p^{x}*q^{(n-x)}}[/tex]

[tex]\mathbf{P(X=x)=\frac{7!}{0!*(7-0)!}*0.14^{0}*0.84^{(7-0)}}[/tex]

[tex]\mathbf{P(X=x)= 1*1*0.84^{(7-0)}}[/tex]

[tex]\mathbf{P(X=x)= 0.347927822}[/tex]



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