Question

For which equations below is x = –3 a possible solution? Check all that apply.


|x| = 3

|x| = –3

|–x| = 3

|–x| = –3

–|x| = –3

–|x| = 3

Answer 1

Correct are the first, the third, and the fifth

Answer 2

Answer:

The correct options are A, C and E.

Step-by-step explanation

If a absolution equation is defined as

$|x|=a$

Then the solutions of the equation are x=a and x=-a.

A.

$|x|=3$

$x=\pm 3$

So,x=-3 is a solution of this equation.

B.

$|x|=-3$

This equation has no solution because the value of |x| can no

be negative.

C.

$|-x|=3$

$-x=\pm 3$

$x=\pm 3$

So,x=-3 is a solution of this equation.

D.

$|-x|=-3$

This equation has no solution because the value of |-x| can no

be negative.

E.

$-|x|=-3$

Divide both sides by -1.

$|x|=3$

$x=\pm 3$

So,x=-3 is a solution of this equation.

F.

$-|x|=3$

Divide both sides by -1.

$|x|=-3$

This equation has no solution because the value of |x| can not be negative.

Therefore the correct options are A, C and E.