Part A:
Let's rewrite the equation [tex]V = \frac{1}{3} \pi r^2 h[/tex] in terms of [tex]r[/tex]:
[tex]V = \frac{1}{3} \pi r^2 h[/tex]
[tex]\dfrac{3V}{\pi} = r^2 h[/tex]
[tex]\dfrac{3V}{h \pi} = r^2[/tex]
[tex]r = \pm \sqrt{\dfrac{3V}{h \pi}}[/tex]
[tex]\boxed{r = \sqrt{\dfrac{3V}{h \pi}}}[/tex]
Part B:
Let's use the equation we just found to find [tex]r[/tex]:
[tex]r = \sqrt{\dfrac{3V}{h \pi}}[/tex]
[tex]r = \sqrt{\dfrac{3(25)}{5 \pi}} = \sqrt{\dfrac{75}{5 \pi}} = \sqrt{\dfrac{15}{\pi}}[/tex]
Our answer is: [tex]\boxed{r = \sqrt{\dfrac{15}{\pi}}}[/tex]