Question

Two cyclist leaves town 200 mi apart at the same time and travel toward each other. One travels at 10mi/h slower than the other. The they meet in 5 hours, what is the rate of each cyclist

Answer 1

Let x be the rate of speed of slower cyclist

and x+10 = rate of speed of faster cyclist

Distance = Speed * Time

5x + 5(x+10) = 200

5x + 5x + 50 = 200

10x = 200-50

10x = 150

x = 15

Rate of speed of slower cyclist: 15 mph

Rate of speed of faster cyclist = 15+10 => 25 mph