the altitude of an airplane is decreasing at a rate of 40 feet per second. what change in the altitude of the airplane over period of 41 seconds?
A. 1,640 feet
B. 81 feet
C. -1, 640 feet
D. -81 feet

Respuesta :

C, it would be 1,640 feet lesser in elevation than it's begining point
The answer would be C, since the airplane is going down at a rate of 40 feet per second and the amount of time it decreased was 41 seconds, you would multiply -40 x 41 which equals to -1,640.
I hope I helped!
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