Question

Find the weight of the same object on a planet where the gravitational attraction has been reduced to 1/10 of the earths pull

Answer 1

"Weight" describes the force of an object due to the mass of the object and the acceleration of that object. Since the gravitational "attraction" (force) is now 1/10 the size, the weight will also be 1/10 the size.

Answer 2

This question deals with the comparison of weight of an object on a planet where the gravitatonal acceleration is one-tentht of the Earth's gravitational acceleration.

The weight of the same object on a planet where the gravitational attraction has been reduced to 1/10 of the earths pull will be "One-tenth of the weight of the object on Earth".

The weight of an object on Earth is given by the following formula:

W = mg  ----------- eqn(1)

where,

W = Weight of object on Earth

m = mass of the object (constant everywhere in the universe)

g = acceleration due to gravity on Earth

For the new planet:

Weight = W'

mass = m

acceleration due to gravity = g' = $\frac{g}{10}$

Therefore,

$W' = m\frac{g}{10}$

using eqn (1)

$W' = \frac{W}{10}$

Hence, the weight on the new planet will be one-tenth the weight on Earth.

The attached picture shows the weight force.

Learn more about weight here:

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