Question

for this triangle what is cos 0 ?
a. 0.60
b. 0.75
c. 0.80
d. 1.25

Answer 1

a.
Since the hyoptenuse is 15 and the opposite is 12, thus the adjacent is 9 as solved by the Pythagoras theorem. Thus, as the cosine rule dictates, adjacent over hyoptenuse, 15 shall be divided by 9 which gets you the answer 0.60

Answer 2

Answer:

$cos\theta=0.6$

Explanation:

In the given triangle, perpendicular distance is 12 units and the hypotenuse of the triangle is 15 units. Let b is the base of the triangle. It can be calculated using the Pythagoras theorem as :

$H^2=P^2+B^2$

$B=\sqrt{H^2-P^2}$

$B=\sqrt{15^2-12^2}$

B = 9 units

Now we need to find the value of $cos\theta$. Using trigonometric identities as :

$cos\theta=\dfrac{B}{H}$

$cos\theta=\dfrac{9}{15}$

$cos\theta=0.6$

So, the value of $cos\theta$ is 0.6. Hence, this is the required solution.