Answer:
-104x^4*y^6
Step-by-step explanation:
Your main job here is to find the product of -2x2y3 and 14x2y3.
Let's begin by using " ^ " to denote exponentiation: -2x^2y^3 · 14x^2y^3 and then reviewing the rule of exponents that applies here:
y^a*y^b = y^(a+b)
Then -2x^2*14x^2 = -28x^(2+2) = -28x^4, and
y^3*y^3 = y^(3+3) = y^6
Then -2x^2y^3 · 14x^2y^3 = -28x^4*y^6, or -104x^4*y^6.
Answer: -28x^4y^6
(This is if you ment to put exponets because I had a simular question on odyssey ware and got it right)
