Answer-
The polynomial function is,
[tex]y=x^4-10x^3+38x^2-64x+40[/tex]
Solution-
The zeros of the polynomial are 2 and (3+i). Root 2 has multiplicity of 2 and (3+i) has multiplicity of 1
The general form of the equation will be,
[tex]\Rightarrow y=(x-(2))^2(x-(3+i))(x-(3-i))[/tex] ( ∵ (3-i) is the conjugate of (3+i) )
[tex]\Rightarrow y=(x-2)^2(x-3-i)(x-3+i)[/tex]
[tex]\Rightarrow y=(x^2-4x+4)((x-3)-i)((x-3)+i)[/tex]
[tex]\Rightarrow y=(x^2-4x+4)((x-3)^2-i^2)[/tex]
[tex]\Rightarrow y=(x^2-4x+4)((x^2-6x+9)+1)[/tex]
[tex]\Rightarrow y=(x^2-4x+4)(x^2-6x+10)[/tex]
[tex]\Rightarrow y=x^2x^2-6x^2x+10x^2-4x^2x+4\cdot \:6xx-4\cdot \:10x+4x^2-4\cdot \:6x+4\cdot \:10[/tex]
[tex]\Rightarrow y=x^4-10x^3+14x^2+24x^2-40x-24x+40[/tex]
[tex]\Rightarrow y=x^4-10x^3+38x^2-64x+40[/tex]
Therefore, this is the required polynomial function.