So for this, since C(x) is the cost, and we are given the cost of $9050, we will plug 9050 into C(x) and solve for x:
[tex]9050=x^2-14x+74[/tex]
So for this, I will be completing the square. Firstly, subtract 74 on both sides of the equation:
[tex]8976=x^2-14x[/tex]
Next, we want to make the right side of the equation a perfect square. To find the constant of this soon-to-be perfect square, you need to divide the x coefficient by 2, square the quotient, then add the result on both sides of the equation. In this case:
-14 ÷ 2 = -7, (-7)² = 49
[tex]9025=x^2-14x+49[/tex]
Next, factor the left side:
[tex]9025=(x-7)^2[/tex]
Next, square root both sides:
[tex]\pm\ 95=x-7[/tex]
Next, add 7 to both sides:
[tex]7\pm 95=x[/tex]
Next, solve the left side twice. Once with the plus symbol, once with the minus symbol:
[tex]102,-88=x[/tex]
Since we cannot have negative units in this context, at the cost of $9050 you can manufacture 102 units.