ANSWER
The first three expressions will simplify to a rational answer.
EXPLANATION
Let us simplify the expressions then we can see which of them are rational.
A.
[tex]7\sqrt{3} \times \sqrt{3}[/tex]
We multiply out the roots to get
[tex]7\sqrt{3} \times \sqrt{3}=7 \times (\sqrt{3})^2[/tex]
This simplifies to
[tex]7\sqrt{3} \times \sqrt{3}=7 \times 3[/tex]
[tex]7\sqrt{3} \times \sqrt{3}=21[/tex]
This is a rational number hence the answer is rational.
B.
[tex]\sqrt{5} \times \sqrt{5}=(\sqrt{5})^2[/tex]
[tex]\sqrt{5} \times \sqrt{5}=5[/tex]
This is also a rational solution.
C.
[tex]2\sqrt{9} \times \sqrt{4}=2\times3\times2[/tex]
[tex]2\sqrt{9} \times \sqrt{4}=12[/tex]
This one too is a rational solution.
D.
[tex]\sqrt{3} \times \sqrt{16}=\sqrt{3}\times4[/tex]
[tex]\sqrt{3} \times \sqrt{16}=4\sqrt{3}[/tex]
This is an irrational answer because √3 is an irrational number and multiplying a rational number, 4 by an irrational number results in an irrational number.