Respuesta :

ANSWER


The first three expressions will simplify to a rational answer.


EXPLANATION


Let us simplify the expressions then we can see which of them are rational.


A.


[tex]7\sqrt{3} \times \sqrt{3}[/tex]



We multiply out the roots to get



[tex]7\sqrt{3} \times \sqrt{3}=7 \times (\sqrt{3})^2[/tex]


This simplifies to





[tex]7\sqrt{3} \times \sqrt{3}=7 \times 3[/tex]






[tex]7\sqrt{3} \times \sqrt{3}=21[/tex]



This is a rational number hence the answer is rational.


B.



[tex]\sqrt{5} \times \sqrt{5}=(\sqrt{5})^2[/tex]





[tex]\sqrt{5} \times \sqrt{5}=5[/tex]



This is also a rational solution.




C.




[tex]2\sqrt{9} \times \sqrt{4}=2\times3\times2[/tex]





[tex]2\sqrt{9} \times \sqrt{4}=12[/tex]



This one too is a rational solution.




D.



[tex]\sqrt{3} \times \sqrt{16}=\sqrt{3}\times4[/tex]




[tex]\sqrt{3} \times \sqrt{16}=4\sqrt{3}[/tex]



This is an irrational answer because √3 is an irrational number and multiplying a rational number, 4 by an irrational number results in an irrational number.



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