Question

Ben has a collection of quarters and nickels worth $5.35. If the number of nickels is 5 less than twice the number of quarters, find the number of each coin.

Answer 1

(q = quarters, n = nickles)

First, create your system of equations:

   25q + 5n = 535 cents

   n = 2q - 5

Second, Substitute for n:

   25q + 5(2q - 5) = 535

Simplify:

   25q + 10q - 25 = 535

Simplify to solve for q:

   35q=560

   q=16

Next, solve for n by plugging the value of q back into the equation:

   n=2q - 5

   n=32-5

   n=27

There would be 16 quarters and 27 nickles.

Hoped this helped!

Answer 2

This is about algebra word problems.

There are 16 quarters and 27 nickels

• Ben has a collection that contains quarters and nickels.

The financial worth of them is $5.35 = 53.

• Now, we are told that the number of nickels he has is five less than two times the number of quarters he has.

If the number of nickels is x and the number of quarters he has is q, then we can write;

n = 2q - 5

• Now, from conversions; one quarter = $0.25 and one nickel = $0.05

Thus;

0.25q + 0.05n = 5.35

Let us put 2q - 5 for n to get;

0.25q + 0.05(2q - 5) = 5.35

0.25q + 0.1q - 0.25 = 5.35

0.35q = 5.35 + 0.25

0.35q = 5.6

q = 16

Thus; n = 2(16) - 5 = 27

Thus, there are 16 quarters and 27 nickels

Read more at; brainly.com/question/16988992