Question

answer the ? below plz and thank you

Answer 1

Step-By-Step Explanation:

For the first one, you need to insert the 4 where the x is located in the function and solve.

$f(x) = 3(x)^2-2(x)$

$f(x) = 3(4)^2-2(4)$

$f(x) = 3(16)-2(4)$

$f(x) = 40-8$

$f(x) = 32$

Answer:

32

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For the second one, the domain is all the x values and the range is all the y values. You have a few order pairs / points. A point has a formate of (x, y).

By knowing a point has a formate of (x, y), we can find the domain by gathering all of our x values and we can find the range by gathering all of our y values.

(x, y)

(1, 3)

(2, 6)

(3, 9)

(4, 12)

x = domain values = {1, 2, 3, 4)

y = range values = {3, 6, 9, 12)

Answer:

domain = {1, 2, 3, 4)

range = {3, 6, 9, 12)