Question

If the temperature remains constant and the initial pressure is 101.3 kpa then what is the new pressure reading when the volume is doubled

Answer 1

Answer:

50.65 kPa

Explanation:

The temperature is constant, so the only variables are pressure and volume.

We can use Boyle’s Law.

$p_{1}V_{1} = p_{2}V_{2}$  

We can solve this equation to get

$p_{2} = p_{1} \times \frac{V_{1}}{ V_{2}}$

$p_{1} = \text{101.3 kPa}; V_{1} = V_{1}$

$p_{2} = ?; V_{2} = 2V_{1}$

$p_{2} = \text{101.3 kPa} \times \frac{V_{1}}{2V_{1}} = \textbf{50.65 kPa}$