The height of a triangular window is 3 feet less than its base. The area the window is 20 ft.? find the dimensions of the window

Respuesta :

Let us assume base of the window = b feet.

Height is 3 feet less than base, that is = (b-3).

Given area of the triangle = 20 feet square.

We know formula for area of a triangle:

Area = [tex]\frac{1}{2}[/tex] × Base × Height

Plugging values in formula, we get

20 = [tex]\frac{1}{2} b \times (b-3)[/tex]

[tex]\mathrm{Multiply\:both\:sides\:by\:}2[/tex]

[tex]40=b\left(b-3\right)[/tex]

[tex]40=b^2-3b[/tex]

[tex]b^2-3b-40=0[/tex]

Factoring quadratic, we get

[tex]\left(b+5\right)\left(b-8\right)[/tex]=0

b+5=0

b=-5

b-8=0

b=8.

For base we can take only positive value.

Therefore, base of the triangle = 8 feet and height = 8 -3 = 5 feet.


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