Answer:
The cashier has 23 dimes and 16 quarters.
Step-by-step explanation:
Let the amount of dimes = d.
And the amount of quarters = q.
We can write 2 equations with the given information.
d = q + 7 --- the amount of dimes is 7 more than the amount of quarters
0.1d + 0.25q = 6.3 --- a dime is 0.1 dollars and a quarter is 0.25 dollars
0.1(q + 7) + 0.25q = 6.3 --- we can substitute q + 7 for d because they have the same value and we need to have only 1 variable to solve
0.1q + 0.7 + 0.25q = 6.3 --- distribute multipliers outside the parenthesis
0.35q + 0.7 = 6.3 --- combine like terms
0.35q = 5.6 --- subtract 0.7 from both sides
q = 16 --- divide both sides by 0.35
The cashier has 16 quarters. We can use this to solve for dimes.
d = q + 7
d = 16 + 7
d = 23
The cashier has 23 dimes and 16 quarters.
0.1d + 0.25q = 6.3
0.1(23) + 0.25(16) = 6.3
2.3 + 4 = 6.3
6.3 = 6.3
The answer is correct.
