Question

if f(1) = 160 and f(n + 1) = -2f(n), what is f(4)?

Answer 1

f(1) = 160

f(2) = f(1+1) = -2f(1)

f(3) = f(2+1)= - 2f(2) = (-2)·(-2)f(1) = 4f(1)

f(4) = f(3+1) = -2f(3) = -2·4f(1) = -8f(1) = - 8·160 = 

Answer 2

Answer:

-1,280

Step-by-step explanation: