Question

Which sum is equivalent to (11k2 + 3k + 1)?

a. (4k2 + k – 5) + (7k2 + 2k + 6)
b. (k2 – 2) + (11k2 + 3k + 3)
c. (8k2 + k) + (3k + 1)
d. (5k + 1) + (6k – 3)

Answer 1

a) 4k^2 + k – 5) + (7k^2 + 2k + 6)

  11k^2 +3k +1

Choice A

Answer 2

A) You can only add together like terms, so adding the k^2, k, and terms without k gives 4k^2+7k^2+2k+k+6-5=11k^2 +3k +1