Respuesta :
I'm assuming you know binomials, trinomials, and the like. So, make the equation equal to zero.
Once you do you'll get,
4x^2 - 12x - 7 = 0.
Now, unfactor into binomials...
(2x+1) (2x-7) = 0.
Solve for both x's.
2x+1=0
2x-7=0
x= -1/2
x= 7/2
So, x is equal to -1/2 and 7/2.
Good luck!
Once you do you'll get,
4x^2 - 12x - 7 = 0.
Now, unfactor into binomials...
(2x+1) (2x-7) = 0.
Solve for both x's.
2x+1=0
2x-7=0
x= -1/2
x= 7/2
So, x is equal to -1/2 and 7/2.
Good luck!
Solve for x: [tex] 4x^{2} -12x = 7[/tex]
Lets set = 0
[tex]4 x^{2} - 12 - 7 = 0[/tex]
Now, let's solve this problem by factoring
In your problem you need those 2 factor which multiply to be 28 and add up to -12 because 4 * 7 = 28
[tex]4 x^{2} + 2x - 14x -7 = 0 2x ( 2x + 1 ) - 7 ( 2x + 1 ) = 0 (2x - 7 ) ( 2x + 1 ) = 0 [/tex]
so now, lets set both the equations for 0.
[tex]2x - 7 = 0[/tex]
[tex]2x = 7 x = 7/2 [/tex]
and [tex]2x + 1 = 0 2x = -1 x= -1/2[/tex]
Lets set = 0
[tex]4 x^{2} - 12 - 7 = 0[/tex]
Now, let's solve this problem by factoring
In your problem you need those 2 factor which multiply to be 28 and add up to -12 because 4 * 7 = 28
[tex]4 x^{2} + 2x - 14x -7 = 0 2x ( 2x + 1 ) - 7 ( 2x + 1 ) = 0 (2x - 7 ) ( 2x + 1 ) = 0 [/tex]
so now, lets set both the equations for 0.
[tex]2x - 7 = 0[/tex]
[tex]2x = 7 x = 7/2 [/tex]
and [tex]2x + 1 = 0 2x = -1 x= -1/2[/tex]