Question

factorise:
3x3-3x2y+xy2-x2y

Answer 1

$3x^3-3x^2y+xy^2-x^2y$

All terms have an x in them, so you factor that out first to get

$x(3x^2 -4xy+y^2)$

Now the 2nd degree equation will be of the form (3x- ... y)(x- ... y) and by just trying you find that the ... is just 1. So the factorization is:

$x(3x - y)(x - y)$