Original length of the rope = 4m
Size of each piece = 3/5 m.
No of cords of same size formed will be
[tex]4 \div \frac{3}{5} \\ = 4 \times \frac{5}{3} \\ = \frac{20}{3} \\ = 6 \frac{2}{3} [/tex]
[tex]Therefore \: the \: person \: will \: make \: \: 6 \frac{2}{3 \: } cords.[/tex]