Question

You begin sliding down a 15∘ ski slope. part a ignoring friction and air resistance, how fast will you be moving after 10 s?

Answer 1

Answer:

25 m/s

Explanation:

This is a uniformly accelerated motion, so the velocity at time time is given by

$v(t) = v_0 +at$

where $v_0$ is the initial velocity and a is the acceleration.

In this problem, the initial velocity is zero: v0=0. The acceleration is the component of the gravitational acceleration projected along the direction of motion, so

$a=g sin \theta = (9.8 m/s^2) sin 15^{\circ}=2.5 m/s^2$

Therefore, the velocity after t=10 s will be

$v(10 s)=at=(2.5 m/s^2)(10 s)=25 m/s$

Answer 2

Answer:

26 m

Explanation:

Vy=V sin angle = 10 sin(15) = 2.6 m/s

V = Vy t = 2.6 . 10 = 26 m