Question

What molality of pentane is obtained by dissolving 15 g pentane, c5h12, in 245.0 g hexane, c6h14?

Answer 1

Answer

• The molality of pentane will be be  0.84 Molality

Data given

• mass of pentane = 15g
• molar mass of pentane = 72.15
• mass of solvent (hexane)  = 245.0 g = 0.245 Kg

Solution

• Molality = (given mass ÷ molar mass ) ÷ 1 Kg of solvent
• Molality = ( 15 ÷ 72.15 ) ÷ 0.245 Kg
• Molality =  0.84