Which one-variable linear equation can be used to find the solution of the system of equations represented by this graph?


A. x = 3
B. 3 – 3x = 3
C. 3x – 3 = 3
D. y = 3x

Which onevariable linear equation can be used to find the solution of the system of equations represented by this graph A x 3 B 3 3x 3 C 3x 3 3 D y 3x class=

Respuesta :

C looks correct


here's a tip use desmos graphing next time

Answer:

The correct option is C. [tex]3x-3=3[/tex]

Step-by-step explanation:

To find the solution of the system of equations represented by the graph we first need to find the equations of both lines.

All horizontal line which intersects the y-axis at the point [tex](0,a)[/tex] can be written as [tex]y=a[/tex]. Therefore, the horizontal line in the graph intersects the y-axis at the point [tex](0,3)[/tex]. Its equation is [tex]y=3[/tex] (I)

For the second line, all line which intersects the x-axis at the point [tex](b,0)[/tex] and the y-axis at the point [tex](0,c)[/tex] can be written as :

[tex]\frac{x}{b}+\frac{y}{c}=1[/tex]

In the graph, the line intersects the x-axis at [tex](1,0)[/tex] and the y-axis at [tex](0,-3)[/tex] so we can write it as :

[tex]\frac{x}{1}+\frac{y}{-3}=1[/tex] ⇒ If we multiply the equation by -3 ⇒ [tex]-3x+y=-3[/tex] (II)

With (I) and (II) we are going to make a one-variable linear equation :

[tex]\left \{ {{y=3} \atop {-3x+y=-3}} \right.[/tex]

If we replace the equation (I) in equation (II) :

[tex]-3x+3=-3[/tex] (III)

If we multiply (III) by -1 ⇒

[tex]3x-3=3[/tex] (III)'

(III)' is the one-variable linear equation that can be used to find the solution of the system of equations represented by the graph. Finally, the correct option is C. [tex]3x-3=3[/tex]

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