Respuesta :

let's bear in mind that a reciprocal is simply the same vale but upside down, so let's check with a couple of numbers, say 5 and 13,


[tex]\bf \begin{cases}5\\[0.8em]\stackrel{reciprocal}{\frac{1}{5}}\end{cases}~\hspace{5em}5\cdot \cfrac{1}{5}\implies \cfrac{5}{5}\implies 1\\\\\\\begin{cases}13\\[0.8em]\stackrel{reciprocal}{\frac{1}{13}}\end{cases}~\hspace{5em}13\cdot \cfrac{1}{13}\implies \cfrac{13}{13}\implies 1[/tex]

Answer:

the answer is true

Step-by-step explanation:

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