Question

Suppose that a laser light, positioned 100 ft from the base of a flag pole, illuminates a flag that is 85 ft above the ground.

What is the angle of inclination (angle of elevation) of the light beam?

Answer 1

Answer:

The angle of inclination (angle of elevation) of the light beam is 40.364...°

Step-by-step explanation:

According to the below diagram, $A$ is the position of the flag which is 85 ft above the ground. That means, $AB= 85$ ft.

$C$ is the position of laser light, which is 100 ft from the base of the flag pole. That means, $BC= 100$ ft.

Suppose, the angle of inclination of the light beam is  $\theta$ degree.

Now in $\triangle ABC$, we will get........

$tan(\theta)= \frac{AB}{BC} \\ \\ tan(\theta)=\frac{85}{100}=0.85 \\ \\ \theta=tan^-^1(0.85)=40.364...$

So, the angle of inclination (angle of elevation) of the light beam is 40.364...°