Respuesta :
Answer:
[tex]x \leq -4[/tex]
Step-by-step explanation:
[tex]-8x+3\geq 27 and -13x+5\geq 57[/tex]
LEts solve each inequality separately. then we find the intersection of both solutions.
[tex]-8x+3\geq 27[/tex]
Subtract 3 on both sides
[tex]-8x\geq 24[/tex]
Divide both sides by [tex]-8[/tex], change the inequality symbol when we divide by negative number
[tex]x \leq -3[/tex]
Now solve the other inequality
[tex]-13x+5\geq 57[/tex]
Subtract 5 on both sides
[tex]-13x\geq 52[/tex]
Now divide both sides by [tex]-13[/tex]
[tex]x \leq -4[/tex]
Now we take the intersection of [tex]x \leq -3[/tex] and [tex]x \leq -4[/tex]
for [tex]x \leq -3[/tex], we shade the number line to the left
[tex]x \leq -4[/tex], shade the number line to the left
Intersection of both graph is [tex]x \leq -4[/tex]