Question

The vertex of this parabola is at (3,-2). when the x-value is 4, the y-value is 3. whatis the coefficient of the squared expression in the parabolas equation

Answer 1

Answer:

The coefficient of the squared expression in the parabolas equation will be 5.

Step-by-step explanation:

The vertex form of parabola is:  $y=a(x-h)^2 +k$ , where $(h,k)$ is the vertex point and $a$ is the coefficient of $x^2$ term.

The vertex is given as $(3,-2)$. That means, $h=3$ and $k=-2$

So, the vertex form will be:  $y=a(x-3)^2-2$

Given that, when the x-value is 4, the y-value is 3. So, plugging these values into the above equation, we will get.....

$3=a(4-3)^2-2\\ \\ 3=a(1)^2-2\\ \\ a=3+2=5$

Thus, the coefficient of the squared expression in the parabolas equation will be 5.

Answer 2

Answer:

5

Step-by-step explanation:

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