Which of the following are roots of the polynomial function?
F(x)=x^3-x^2-5x-3
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Try this option:
the function can be re-written in a form f(x)=(x+1)(x+1)(x-3);
The roots of the function are 3 and -1
Answer with explanation:
The given Polynomial function is:
F(x)= x³-x²-5 x -3
By Rational root theorem , roots of the polynomial can be 1,-1, 3 ,-3.
F(3)=3³-3²-5×3-3
=27-9-15-3
= 0
So, 3 is one of the root of the equation.
That is, (x-3) will divide the whole polynomial.
F(x)=x³-x²-5 x -3
=(x-3)(x²+2 x +1)
= (x-3)(x+1)²
to get the roots.
1. x-3=0
⇒x=3
2.(x+1)²=0
⇒x+1=0
⇒x= -1
So, root of the polynomial function are=3, and ,-1.
Option B=3 and Option C= -1