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Help!
which sum is rational?

A.)
[tex]\pi + 18[/tex]
B.)
[tex] \sqrt{25 + 1.75} [/tex]
C.
[tex] \sqrt{3 + 5.5} [/tex]
D.)
[tex]\pi + \sqrt{2} [/tex]

Respuesta :

gmany

[tex]\pi+18-irrational\ because\ \pi\ is\ irrational\\\\\sqrt{25+1.75}=\sqrt{26.75}=\sqrt{\dfrac{2675}{100}}=\dfrac{\sqrt{2675}}{\sqrt{100}}=\dfrac{\sqrt{25\cdot107}}{10}\\\\=\dfrac{\sqrt{25}\cdot\sqrt{107}}{10}=\dfrac{5\sqrt{107}}{10}=\dfrac{\sqrt{107}}{2}-irrational\\\\\sqrt{3+5.5}=\sqrt{8.5}=\sqrt{\dfrac{85}{10}}=\sqrt{\dfrac{850}{100}}=\dfrac{\sqrt{850}}{\sqrt{100}}=\dfrac{\sqrt{25\cdot34}}{10}\\\\=\dfrac{\sqrt{25}\cdot\sqrt{34}}{10}=\dfrac{5\sqrt{34}}{10}=\dfrac{\sqrt{34}}{2}-irrational[/tex]

[tex]\pi+\sqrt2-irrational[/tex]

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