Question

A free falling object has the velocity time graph shown. What is the objects displacement between 0.0 and 6.0s

Answer 1

For free fall motion the displacement can be found by graphically as well as by kinematics equation

Here acceleration of object is constant as it fall due to gravity so we can use

$d = v_i * t + \frac{1}{2}at^2$

here if body starts with zero initial speed then we can say

$d = 0 + \frac{1}{2}*9.8*t^2$

here we need to find the displacement from t = 0 to t = 6s

so we can say

$d = \frac{1}{2}*9.8*6^2$

$d = 176.4 m$

so the displacement will be 176.4 m

in order to find the displacement from the graph of velocity and time we need to find the area under the graph for given time interval that will also give us same displacement for given period of time.

Answer 2

Answer:

+360m

Explanation:

You are missing some parts of the question but I have found them else where. The graph will be shown below.

The formula for this is [ d = vt ] where v = velocity and t = time.

On the graph, we can see that the acceleration is constant. The line goes to a maximum velocity of 60m/s and a maximum time of 6 seconds.

Find the displacement with what we are given.

d = 60 * 6

d = 360m

Since we are going forward, we are going to add a "+" sign in front.

Best of Luck!